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authorAlyssa Rosenzweig <[email protected]>2019-09-22 09:01:07 -0400
committerAlyssa Rosenzweig <[email protected]>2019-09-30 08:40:13 -0400
commit72a03bcafae8903339329ee74ba4cdd0c75b2814 (patch)
tree071cf610481d885acbae0c9ee02d5d3255238281 /src
parentb5396369d2f4cc4bbff3bd2bf0639257ffb6fde5 (diff)
pan/midgard: Add mir_choose_bundle helper
It's not always obvious what the optimal bundle type should be. Let's break out the logic to decide. Currently set for purely in-order operation. Signed-off-by: Alyssa Rosenzweig <[email protected]>
Diffstat (limited to 'src')
-rw-r--r--src/panfrost/midgard/midgard_schedule.c25
1 files changed, 25 insertions, 0 deletions
diff --git a/src/panfrost/midgard/midgard_schedule.c b/src/panfrost/midgard/midgard_schedule.c
index 8f324805cdb..969460235d1 100644
--- a/src/panfrost/midgard/midgard_schedule.c
+++ b/src/panfrost/midgard/midgard_schedule.c
@@ -861,6 +861,31 @@ mir_choose_instruction(
return instructions[best_index];
}
+/* Still, we don't choose instructions in a vacuum. We need a way to choose the
+ * best bundle type (ALU, load/store, texture). Nondestructive. */
+
+static unsigned
+mir_choose_bundle(
+ midgard_instruction **instructions,
+ BITSET_WORD *worklist, unsigned count)
+{
+ /* At the moment, our algorithm is very simple - use the bundle of the
+ * best instruction, regardless of what else could be scheduled
+ * alongside it. This is not optimal but it works okay for in-order */
+
+ struct midgard_predicate predicate = {
+ .tag = ~0,
+ .destructive = false
+ };
+
+ midgard_instruction *chosen = mir_choose_instruction(instructions, worklist, count, &predicate);
+
+ if (chosen)
+ return chosen->type;
+ else
+ return ~0;
+}
+
/* Schedule a single block by iterating its instruction to create bundles.
* While we go, tally about the bundle sizes to compute the block size. */