python: Open the template as text, with an explicit encoding

In commit bd27203f4d808763ac24ac94eb677cacf3e7cb99 we changed this to
open in binary mode, to then explicitly decode the lines with the right
encoding.

Unfortunately, that broke the build on Windows, where the template file
can have '\r\n' as line terminators: opening in binary mode would keep
those terminators and break the regexp.

We need to go back to text mode, where the "universal newlines" mode
takes care of this.

However, to fix the initial issue, let's specify the encoding explicitly
when opening the file, and make sure it is open in text mode, so we only
get unicode strings.

Reviewed-by: Jose Fonseca <jfonseca@vmware>

1 files changed, 2 insertions, 3 deletions

diff --git a/src/util/xmlpool/gen_xmlpool.py b/src/util/xmlpool/gen_xmlpool.py
index 64e631f74c4..56a67bcab55 100644
--- a/src/util/xmlpool/gen_xmlpool.py
+++ b/src/util/xmlpool/gen_xmlpool.py
@@ -9,6 +9,7 @@
 
 from __future__ import print_function
 
+import io
 import sys
 import gettext
 import re
@@ -187,11 +188,9 @@ print("/***********************************************************************\
 
 # Process the options template and generate options.h with all
 # translations.
-template = open (template_header_path, "rb")
+template = io.open (template_header_path, mode="rt", encoding='utf-8')
 descMatches = []
 for line in template:
-    line = line.decode('utf-8')
-
     if len(descMatches) > 0:
         matchENUM     = reENUM    .match (line)
         matchDESC_END = reDESC_END.match (line)