glsl: Initialize all member variables of _mesa_glsl_parse_state on construction.

The _mesa_glsl_parse_state object relies on the memory allocator
zeroing out its contents before it's initialized, which is quite an
unusual practice in the C++ world because it ties objects to some
specific allocation scheme, and gives unpredictable results when an
object is created with a different allocator -- Stack allocation,
array allocation, or aggregation inside a different object are some of
the useful possibilities that come to my mind.  Initialize all fields
from the constructor and stop using the zeroing allocator.

Reviewed-by: Paul Berry <[email protected]>
Reviewed-by: Chad Versace <[email protected]>
Reviewed-by: Kenneth Graunke <[email protected]>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/glsl/glsl_parser_extras.h b/src/glsl/glsl_parser_extras.h
index cef4436f672..d557f8ba69d 100644
--- a/src/glsl/glsl_parser_extras.h
+++ b/src/glsl/glsl_parser_extras.h
@@ -73,7 +73,7 @@ struct _mesa_glsl_parse_state {
    _mesa_glsl_parse_state(struct gl_context *_ctx, GLenum target,
 			  void *mem_ctx);
 
-   DECLARE_RZALLOC_CXX_OPERATORS(_mesa_glsl_parse_state);
+   DECLARE_RALLOC_CXX_OPERATORS(_mesa_glsl_parse_state);
 
    /**
     * Generate a string representing the GLSL version currently being compiled