glsl: Disallow primitive type layout qualifier on variables.

This only makes any sense on the GS input or output layout declaration,
nowhere else.

Fixes the piglit tests:

  * spec/glsl-1.50/compiler/incorrect-in-layout-qualifiers-with-variable-declarations.geom
  * spec/glsl-1.50/compiler/incorrect-out-layout-qualifiers-with-variable-declarations.geom
  * spec/glsl-1.50/compiler/layout-fs-no-output.frag
  * spec/glsl-1.50/compiler/layout-vs-no-input.vert
  * spec/glsl-1.50/compiler/layout-vs-no-output.vert

Signed-off-by: Chris Forbes <[email protected]>
Reviewed-by: Kenneth Graunke <[email protected]>

1 files changed, 7 insertions, 0 deletions

diff --git a/src/glsl/ast_to_hir.cpp b/src/glsl/ast_to_hir.cpp
index 132a955b781..92e0f90b81c 100644
--- a/src/glsl/ast_to_hir.cpp
+++ b/src/glsl/ast_to_hir.cpp
@@ -2469,6 +2469,13 @@ apply_type_qualifier_to_variable(const struct ast_type_qualifier *qual,
                        _mesa_shader_stage_to_string(state->stage));
    }
 
+   /* Disallow layout qualifiers which may only appear on layout declarations. */
+   if (qual->flags.q.prim_type) {
+      _mesa_glsl_error(loc, state,
+                       "Primitive type may only be specified on GS input or output "
+                       "layout declaration, not on variables.");
+   }
+
    /* Section 6.1.1 (Function Calling Conventions) of the GLSL 1.10 spec says:
     *
     *     "However, the const qualifier cannot be used with out or inout."