glsl: make component_slots() returns 2 for samplers/images

Bindless samplers/images are 64-bit unsigned integers, which
means they consume two components as specified by
ARB_bindless_texture.

It looks like we are not wasting uniform storage by changing
this because default-block uniforms are not packed. So, if
we use N uint uniforms, they occupy N * 16 bytes in the
constant buffer. This is something that could be improved.

Though, count_uniform_size needs to be adjusted to not count
a sampler (or image) twice.

As a side effect, this will probably break the cache if you
have one because it will consider sampler/image types as
two components.

v3: - update the comments

Signed-off-by: Samuel Pitoiset <[email protected]>
Reviewed-by: Nicolai Hähnle <[email protected]>
Reviewed-by: Timothy Arceri <[email protected]>

1 files changed, 6 insertions, 2 deletions

diff --git a/src/compiler/glsl/link_uniforms.cpp b/src/compiler/glsl/link_uniforms.cpp
index c195e767e25..f6335b0f9eb 100644
--- a/src/compiler/glsl/link_uniforms.cpp
+++ b/src/compiler/glsl/link_uniforms.cpp
@@ -340,9 +340,13 @@ private:
       if (type->contains_subroutine()) {
          this->num_shader_subroutines += values;
       } else if (type->contains_sampler()) {
-         this->num_shader_samplers += values;
+         /* Samplers (bound or bindless) are counted as two components as
+          * specified by ARB_bindless_texture. */
+         this->num_shader_samplers += values / 2;
       } else if (type->contains_image()) {
-         this->num_shader_images += values;
+         /* Images (bound or bindless) are counted as two components as
+          * specified by ARB_bindless_texture. */
+         this->num_shader_images += values / 2;
 
          /* As drivers are likely to represent image uniforms as
           * scalar indices, count them against the limit of uniform