glsl: allow ?: operator with images and samplers when bindless is enabled

Signed-off-by: Rhys Perry <[email protected]>
Signed-off-by: Marek Olšák <[email protected]>

1 files changed, 5 insertions, 3 deletions

diff --git a/src/compiler/glsl/ast_to_hir.cpp b/src/compiler/glsl/ast_to_hir.cpp
index dd60a2a87fd..74160ec142b 100644
--- a/src/compiler/glsl/ast_to_hir.cpp
+++ b/src/compiler/glsl/ast_to_hir.cpp
@@ -1850,9 +1850,11 @@ ast_expression::do_hir(exec_list *instructions,
        *   expressions; such use results in a compile-time error."
        */
       if (type->contains_opaque()) {
-         _mesa_glsl_error(&loc, state, "opaque variables cannot be operands "
-                          "of the ?: operator");
-         error_emitted = true;
+         if (!(state->has_bindless() && (type->is_image() || type->is_sampler()))) {
+            _mesa_glsl_error(&loc, state, "variables of type %s cannot be "
+                             "operands of the ?: operator", type->name);
+            error_emitted = true;
+         }
       }
 
       ir_constant *cond_val = op[0]->constant_expression_value(ctx);