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authorTimothy Arceri <[email protected]>2018-04-09 14:40:40 +1000
committerMatt Turner <[email protected]>2019-01-09 16:42:40 -0800
commit76c27e47b90647df047e785d6b3ab5d0d979a1ee (patch)
treea71f2a7343e3c1fc06f632647dd61649c90a6ece /src/compiler/glsl/glsl_parser.yy
parent63f6d7afd6fab91ec3ef6b8fec61401d8faf5587 (diff)
glsl: Copy function out to temp if we don't directly ref a variable
Otherwise we can end up with IR that looks like this: ( (declare (temporary ) vec4 f@8) (assign (xyzw) (var_ref f@8) (var_ref f) ) (call f16 ((swiz y (var_ref f@8) ))) (assign (xyzw) (var_ref f) (var_ref f@8) ) )) When we really need: (declare (temporary ) float inout_tmp) (assign (x) (var_ref inout_tmp) (swiz y (var_ref f) )) (call f16 ((var_ref inout_tmp) )) (assign (y) (var_ref f) (swiz y (swiz xxxx (var_ref inout_tmp) ))) (declare (temporary ) void void_var) The GLSL IR function inlining code seemed to produce correct code even without this but we need the correct IR for GLSL IR -> NIR to be able to understand whats going on. Reviewed-by: Kenneth Graunke <[email protected]>
Diffstat (limited to 'src/compiler/glsl/glsl_parser.yy')
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