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authorDanylo Piliaiev <[email protected]>2019-03-25 14:15:27 +0200
committerLionel Landwerlin <[email protected]>2019-04-16 09:42:08 +0000
commit04508f57d1d36587f3cc048f0f5dae0611f9330c (patch)
tree21bc629a1cfc41c3884466600b19a7e786310641
parent9b2473c7a4427371f9c7ab07ee3c4408b9995207 (diff)
intel/compiler: Do not reswizzle dst if instruction writes to flag register
If we write to the flag register changing the swizzle would change what channels are written to the flag register. Bugzilla: https://bugs.freedesktop.org/show_bug.cgi?id=110201 Fixes: 4cd1a0be Signed-off-by: Danylo Piliaiev <[email protected]> Reviewed-by: <[email protected]>
-rw-r--r--src/intel/compiler/brw_vec4.cpp6
1 files changed, 6 insertions, 0 deletions
diff --git a/src/intel/compiler/brw_vec4.cpp b/src/intel/compiler/brw_vec4.cpp
index bb8b554c852..7d60665b621 100644
--- a/src/intel/compiler/brw_vec4.cpp
+++ b/src/intel/compiler/brw_vec4.cpp
@@ -1154,6 +1154,12 @@ vec4_instruction::can_reswizzle(const struct gen_device_info *devinfo,
if (devinfo->gen == 6 && is_math() && swizzle != BRW_SWIZZLE_XYZW)
return false;
+ /* If we write to the flag register changing the swizzle would change
+ * what channels are written to the flag register.
+ */
+ if (writes_flag())
+ return false;
+
/* We can't swizzle implicit accumulator access. We'd have to
* reswizzle the producer of the accumulator value in addition
* to the consumer (i.e. both MUL and MACH). Just skip this.